Integrand size = 25, antiderivative size = 863 \[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\frac {a \arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \arctan \left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \arctan \left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (-\frac {\sqrt {a-b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right ),-1\right ) \sqrt {e \tan (c+d x)}}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {\sqrt {a-b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right ),-1\right ) \sqrt {e \tan (c+d x)}}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3} \]
[Out]
Time = 1.52 (sec) , antiderivative size = 863, normalized size of antiderivative = 1.00, number of steps used = 39, number of rules used = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.920, Rules used = {3978, 3967, 3969, 3557, 335, 303, 1176, 631, 210, 1179, 642, 2693, 2695, 2652, 2719, 3975, 2812, 2809, 2985, 2984, 504, 1227, 551} \[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\frac {2 \sqrt {2} \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (-\frac {\sqrt {a-b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)+1}}\right ),-1\right ) \sqrt {e \tan (c+d x)} b^3}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {2 \sqrt {2} \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {\sqrt {a-b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)+1}}\right ),-1\right ) \sqrt {e \tan (c+d x)} b^3}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right ) b^2}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {\arctan \left (\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}+1\right ) b^2}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {\log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}-\sqrt {2} \sqrt {e \tan (c+d x)}\right ) b^2}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {\log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}+\sqrt {2} \sqrt {e \tan (c+d x)}\right ) b^2}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 \cos (c+d x) (e \tan (c+d x))^{3/2} b}{\left (a^2-b^2\right ) d e^3}+\frac {2 \cos (c+d x) E\left (\left .c+d x-\frac {\pi }{4}\right |2\right ) \sqrt {e \tan (c+d x)} b}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}+\frac {a \arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \arctan \left (\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}+1\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}} \]
[In]
[Out]
Rule 210
Rule 303
Rule 335
Rule 504
Rule 551
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1227
Rule 2652
Rule 2693
Rule 2695
Rule 2719
Rule 2809
Rule 2812
Rule 2984
Rule 2985
Rule 3557
Rule 3967
Rule 3969
Rule 3975
Rule 3978
Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {a-b \sec (c+d x)}{(e \tan (c+d x))^{3/2}} \, dx}{a^2-b^2}+\frac {b^2 \int \frac {\sqrt {e \tan (c+d x)}}{a+b \sec (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2} \\ & = -\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 \int \left (-\frac {a}{2}-\frac {1}{2} b \sec (c+d x)\right ) \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}+\frac {b^2 \int \sqrt {e \tan (c+d x)} \, dx}{a \left (a^2-b^2\right ) e^2}-\frac {b^3 \int \frac {\sqrt {e \tan (c+d x)}}{b+a \cos (c+d x)} \, dx}{a \left (a^2-b^2\right ) e^2} \\ & = -\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {a \int \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}-\frac {b \int \sec (c+d x) \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}+\frac {b^2 \text {Subst}\left (\int \frac {\sqrt {x}}{e^2+x^2} \, dx,x,e \tan (c+d x)\right )}{a \left (a^2-b^2\right ) d e}-\frac {\left (b^3 \sqrt {e \cot (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \frac {1}{(b+a \cos (c+d x)) \sqrt {e \cot (c+d x)}} \, dx}{a \left (a^2-b^2\right ) e^2} \\ & = -\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}+\frac {(2 b) \int \cos (c+d x) \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}-\frac {a \text {Subst}\left (\int \frac {\sqrt {x}}{e^2+x^2} \, dx,x,e \tan (c+d x)\right )}{\left (a^2-b^2\right ) d e}+\frac {\left (2 b^2\right ) \text {Subst}\left (\int \frac {x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{a \left (a^2-b^2\right ) d e}-\frac {\left (b^3 \sqrt {-\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \frac {\sqrt {\sin (c+d x)}}{\sqrt {-\cos (c+d x)} (b+a \cos (c+d x))} \, dx}{a \left (a^2-b^2\right ) e^2 \sqrt {\sin (c+d x)}} \\ & = -\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}-\frac {(2 a) \text {Subst}\left (\int \frac {x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{\left (a^2-b^2\right ) d e}-\frac {b^2 \text {Subst}\left (\int \frac {e-x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{a \left (a^2-b^2\right ) d e}+\frac {b^2 \text {Subst}\left (\int \frac {e+x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{a \left (a^2-b^2\right ) d e}+\frac {\left (2 b \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \sqrt {\sin (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2 \sqrt {\sin (c+d x)}}-\frac {\left (b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)} (b+a \cos (c+d x))} \, dx}{a \left (a^2-b^2\right ) e^2 \sqrt {\sin (c+d x)}} \\ & = -\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}+\frac {b^2 \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}+2 x}{-e-\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}-2 x}{-e+\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \text {Subst}\left (\int \frac {e-x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{\left (a^2-b^2\right ) d e}-\frac {a \text {Subst}\left (\int \frac {e+x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{\left (a^2-b^2\right ) d e}+\frac {b^2 \text {Subst}\left (\int \frac {1}{e-\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 a \left (a^2-b^2\right ) d e}+\frac {b^2 \text {Subst}\left (\int \frac {1}{e+\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 a \left (a^2-b^2\right ) d e}-\frac {\left (4 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {1-x^4} \left (a+b+(-a+b) x^4\right )} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}+\frac {\left (2 b \cos (c+d x) \sqrt {e \tan (c+d x)}\right ) \int \sqrt {\sin (2 c+2 d x)} \, dx}{\left (a^2-b^2\right ) e^2 \sqrt {\sin (2 c+2 d x)}} \\ & = \frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}-\frac {a \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}+2 x}{-e-\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}-2 x}{-e+\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \text {Subst}\left (\int \frac {1}{e-\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \left (a^2-b^2\right ) d e}-\frac {a \text {Subst}\left (\int \frac {1}{e+\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \left (a^2-b^2\right ) d e}-\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {a+b}-\sqrt {a-b} x^2\right ) \sqrt {1-x^4}} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}+\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {a+b}+\sqrt {a-b} x^2\right ) \sqrt {1-x^4}} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}} \\ & = -\frac {b^2 \arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \arctan \left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}-\frac {a \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+x^2} \left (\sqrt {a+b}-\sqrt {a-b} x^2\right )} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}+\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+x^2} \left (\sqrt {a+b}+\sqrt {a-b} x^2\right )} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}} \\ & = \frac {a \arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \arctan \left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \arctan \left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \arctan \left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (-\frac {\sqrt {a-b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right ),-1\right ) \sqrt {e \tan (c+d x)}}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {\sqrt {a-b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right ),-1\right ) \sqrt {e \tan (c+d x)}}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 23.90 (sec) , antiderivative size = 1571, normalized size of antiderivative = 1.82 \[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\frac {(b+a \cos (c+d x)) \sec (c+d x) \left (-\frac {2 (b-a \cos (c+d x)) \csc (c+d x)}{-a^2+b^2}+\frac {2 b \sin (c+d x)}{-a^2+b^2}\right ) \tan ^2(c+d x)}{d (a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}}+\frac {(b+a \cos (c+d x)) \sec (c+d x) \tan ^{\frac {3}{2}}(c+d x) \left (-\frac {\left (-a^2+3 b^2\right ) \sec (c+d x) \left (6 \sqrt {2} \left (a^2-b^2\right ) \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )-6 \sqrt {2} a^2 \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )+6 \sqrt {2} b^2 \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )-(6+6 i) \sqrt {b} \left (a^2-b^2\right )^{3/4} \arctan \left (1-\frac {(1+i) \sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )+(6+6 i) \sqrt {b} \left (a^2-b^2\right )^{3/4} \arctan \left (1+\frac {(1+i) \sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-3 \sqrt {2} a^2 \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )+3 \sqrt {2} b^2 \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )+3 \sqrt {2} a^2 \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )-3 \sqrt {2} b^2 \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )+(3+3 i) \sqrt {b} \left (a^2-b^2\right )^{3/4} \log \left (\sqrt {a^2-b^2}-(1+i) \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\tan (c+d x)}+i b \tan (c+d x)\right )-(3+3 i) \sqrt {b} \left (a^2-b^2\right )^{3/4} \log \left (\sqrt {a^2-b^2}+(1+i) \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\tan (c+d x)}+i b \tan (c+d x)\right )+8 a b \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},-\tan ^2(c+d x),\frac {b^2 \tan ^2(c+d x)}{a^2-b^2}\right ) \tan ^{\frac {3}{2}}(c+d x)\right ) \left (a+b \sqrt {1+\tan ^2(c+d x)}\right )}{12 \left (a^3-a b^2\right ) (b+a \cos (c+d x)) \left (1+\tan ^2(c+d x)\right )}+\frac {b \cos (2 (c+d x)) \sec ^2(c+d x) \left (-84 \sqrt {2} b \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )+84 \sqrt {2} b \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )+\frac {(42+42 i) \left (-a^2+2 b^2\right ) \arctan \left (1-\frac {(1+i) \sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )}{\sqrt {b} \sqrt [4]{a^2-b^2}}+\frac {(42+42 i) \left (a^2-2 b^2\right ) \arctan \left (1+\frac {(1+i) \sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )}{\sqrt {b} \sqrt [4]{a^2-b^2}}+42 \sqrt {2} b \log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )-42 \sqrt {2} b \log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )+\frac {(21+21 i) \left (a^2-2 b^2\right ) \log \left (\sqrt {a^2-b^2}-(1+i) \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\tan (c+d x)}+i b \tan (c+d x)\right )}{\sqrt {b} \sqrt [4]{a^2-b^2}}+\frac {(21+21 i) \left (-a^2+2 b^2\right ) \log \left (\sqrt {a^2-b^2}+(1+i) \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\tan (c+d x)}+i b \tan (c+d x)\right )}{\sqrt {b} \sqrt [4]{a^2-b^2}}+\frac {112 a^3 \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},-\tan ^2(c+d x),\frac {b^2 \tan ^2(c+d x)}{a^2-b^2}\right ) \tan ^{\frac {3}{2}}(c+d x)}{a^2-b^2}-\frac {168 a b^2 \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},-\tan ^2(c+d x),\frac {b^2 \tan ^2(c+d x)}{a^2-b^2}\right ) \tan ^{\frac {3}{2}}(c+d x)}{a^2-b^2}-\frac {24 a b^2 \operatorname {AppellF1}\left (\frac {7}{4},\frac {1}{2},1,\frac {11}{4},-\tan ^2(c+d x),\frac {b^2 \tan ^2(c+d x)}{a^2-b^2}\right ) \tan ^{\frac {7}{2}}(c+d x)}{a^2-b^2}-\frac {168 a \tan ^{\frac {3}{2}}(c+d x)}{\sqrt {1+\tan ^2(c+d x)}}\right ) \left (a+b \sqrt {1+\tan ^2(c+d x)}\right )}{84 a (b+a \cos (c+d x)) \left (-1+\tan ^2(c+d x)\right ) \sqrt {1+\tan ^2(c+d x)}}\right )}{(a-b) (a+b) d (a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 4015 vs. \(2 (746 ) = 1492\).
Time = 3.27 (sec) , antiderivative size = 4016, normalized size of antiderivative = 4.65
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Timed out. \[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\int \frac {1}{\left (e \tan {\left (c + d x \right )}\right )^{\frac {3}{2}} \left (a + b \sec {\left (c + d x \right )}\right )}\, dx \]
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\[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\int { \frac {1}{{\left (b \sec \left (d x + c\right ) + a\right )} \left (e \tan \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \]
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\[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\int { \frac {1}{{\left (b \sec \left (d x + c\right ) + a\right )} \left (e \tan \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx=\int \frac {\cos \left (c+d\,x\right )}{{\left (e\,\mathrm {tan}\left (c+d\,x\right )\right )}^{3/2}\,\left (b+a\,\cos \left (c+d\,x\right )\right )} \,d x \]
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